m^2=68-5m

Solution for m^2=68-5m equation:

m^2=68-5m

We move all terms to the left:

m^2-(68-5m)=0

We add all the numbers together, and all the variables

m^2-(-5m+68)=0

We get rid of parentheses

m^2+5m-68=0

a = 1; b = 5; c = -68;
Δ = b2-4ac
Δ = 52-4·1·(-68)
Δ = 297
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{297}=\sqrt{9*33}=\sqrt{9}*\sqrt{33}=3\sqrt{33}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3\sqrt{33}}{2*1}=\frac{-5-3\sqrt{33}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3\sqrt{33}}{2*1}=\frac{-5+3\sqrt{33}}{2}
$